Six years ago, a father was 4 times as old as his son. The sum of their present ages is 52 years. What is the father's present age?
A40 years
B32 years
C36 years
D38 years
Show answer & solution
Answer: D. 38 years
Solution
Let present ages be F and S.
F - 6 = 4 (S - 6) and F + S = 52
F = 4S - 18, so 5S - 18 = 52, S = 14
F = 52 - 14 = 38 years
Check: 6 years ago F = 32 and S = 8, and 32 = 4 x 8
Answer: 38 years
After 5 years, a mother will be 3 times as old as her daughter. The difference between their present ages is 20 years. What is the daughter's present age?
A5 years
B10 years
C15 years
D8 years
Show answer & solution
Answer: A. 5 years
Solution
Let mother = M, daughter = D.
M = D + 20 and M + 5 = 3 (D + 5)
D + 25 = 3D + 15, so 2D = 10 and D = 5
M = 25; check: after 5 years 30 = 3 x 10
Answer: 5 years
The average age of a family of 5 members is 24 years. The youngest member is 8 years old. What was the average age of the family just before the youngest member was born?
A22 years
B20 years
C24 years
D18 years
Show answer & solution
Answer: B. 20 years
Solution
Total age now = 5 x 24 = 120
Other 4 members now = 120 - 8 = 112
When the youngest was born (8 years ago) the 4 members were 112 - 4 x 8 = 80 in total
Average = 80 / 4 = 20 years
Answer: 20 years
The average age of 8 persons is 28 years. A person aged 44 years leaves the group and is replaced by a person aged 20 years. What is the new average age?
A26 years
B25 years
C27 years
D24 years
Show answer & solution
Answer: B. 25 years
Solution
Original total = 8 x 28 = 224
New total = 224 - 44 + 20 = 200
New average = 200 / 8 = 25 years
Answer: 25 years
Ravi is 6 years older than Meena. Four years ago the ratio of their ages was 5 : 4. What is Meena's present age?
A30 years
B24 years
C28 years
D34 years
Show answer & solution
Answer: C. 28 years
Solution
Let Meena = m, Ravi = m + 6.
(m + 6 - 4)/(m - 4) = 5/4
4m + 8 = 5m - 20, so m = 28
Check: 4 years ago Ravi = 30, Meena = 24; 30 : 24 = 5 : 4
Answer: 28 years
A's age after 10 years will be twice B's age 10 years ago. If A is 9 years older than B, what is B's present age?
A29 years
B48 years
C49 years
D39 years
Show answer & solution
Answer: D. 39 years
Solution
Let B = b, A = b + 9.
b + 9 + 10 = 2 (b - 10)
b + 19 = 2b - 20, so b = 39 years
Check: A = 48; after 10 years 58 = 2 x 29 (B 10 years ago)
Answer: 39 years
The total of the ages of three persons 10 years ago was 54 years. What will be the total of their ages 5 years from now?
A99 years
B84 years
C69 years
D89 years
Show answer & solution
Answer: A. 99 years
Solution
Total 10 years ago = 54
Each person has aged 10 + 5 = 15 years, so for three persons: 3 x 15 = 45
Total after 5 years = 54 + 45 = 99 years
Answer: 99 years
Rohit is 3 times as old as Sohan. After 5 years he will be twice as old as Sohan. After how many years from now will the sum of their ages be 60?
A15 years
B20 years
C25 years
D10 years
Show answer & solution
Answer: B. 20 years
Solution
Let Sohan = x, Rohit = 3x.
3x + 5 = 2 (x + 5), so x = 5 and Rohit = 15
Sum now = 15 + 5 = 20
Each year the sum increases by 2 (both age by 1)
Years needed = (60 - 20)/2 = 20
Answer: 20 years
Ravi is twice as old as Sita was when Ravi was as old as Sita is now. If the sum of their present ages is 56 years, how old is Ravi?
A24 years
B28 years
C36 years
D32 years
Show answer & solution
Answer: D. 32 years
Solution
Let Ravi = R, Sita = S (R > S). The gap is R - S years.
When Ravi was S years old (R - S years ago), Sita was S - (R - S) = 2S - R.
R = 2 (2S - R), so 3R = 4S and R : S = 4 : 3
R + S = 56, so R = 32 and S = 24
Check: 8 years ago Ravi was 24 and Sita 16; 32 = 2 x 16
Answer: 32 years
The ages of A and B are in the ratio 5 : 7. After 6 years the ratio of their ages will be 3 : 4. What is B's present age?
A42 years
B30 years
C35 years
D48 years
Show answer & solution
Answer: A. 42 years
Solution
Let ages be 5x and 7x.
(5x + 6)/(7x + 6) = 3/4
20x + 24 = 21x + 18, so x = 6
B = 7 x 6 = 42 years
Check: after 6 years 36 : 48 = 3 : 4
Answer: 42 years
The present ages of three persons are in the ratio 4 : 7 : 9. Eight years ago, the sum of their ages was 56 years. What is the age of the youngest person now?
A12 years
B16 years
C20 years
D28 years
Show answer & solution
Answer: B. 16 years
Solution
Let ages be 4x, 7x, 9x.
Eight years ago the sum = 20x - 3 x 8 = 20x - 24
20x - 24 = 56, so x = 4
Youngest = 4 x 4 = 16 years
Answer: 16 years
A father's age is 3 years more than 3 times his son's age. Three years from now, the father's age will be 10 years more than twice the son's age. What is the father's present age?
A30 years
B36 years
C33 years
D43 years
Show answer & solution
Answer: C. 33 years
Solution
Let son = s, father = 3s + 3.
After 3 years: 3s + 6 = 2 (s + 3) + 10
3s + 6 = 2s + 16, so s = 10
Father = 3 x 10 + 3 = 33 years
Answer: 33 years
A mother was 28 years old when her first child was born and 32 years old when her second child was born. At present the sum of the ages of the two children equals the mother's age. How old is the mother?
A56 years
B64 years
C48 years
D60 years
Show answer & solution
Answer: D. 60 years
Solution
Let mother's present age = M.
First child = M - 28, second child = M - 32
M = (M - 28) + (M - 32) = 2M - 60, so M = 60 years
Children are 32 and 28 years old: 32 + 28 = 60
Answer: 60 years
The sum of the ages of a father and his son is 45 years. Five years ago, the product of their ages was 4 times the father's age at that time. What is the father's present age?
A36 years
B34 years
C39 years
D40 years
Show answer & solution
Answer: A. 36 years
Solution
Let father = f, son = s. f + s = 45.
Five years ago: (f - 5)(s - 5) = 4 (f - 5)
Divide by (f - 5): s - 5 = 4, so s = 9
f = 45 - 9 = 36 years
Answer: 36 years
A father is 30 years older than his son. Five years ago the father's age was 4 times the son's age. After how many years from now will the father be twice as old as the son?
A10 years
B20 years
C15 years
D5 years
Show answer & solution
Answer: C. 15 years
Solution
Let son = s, father = s + 30.
s + 25 = 4 (s - 5), so 3s = 45 and s = 15; father = 45
Let it happen after x years: 45 + x = 2 (15 + x)
45 + x = 30 + 2x, so x = 15
Answer: 15 years
Three years ago the ratio of the ages of A and B was 3 : 4. Three years from now it will be 5 : 6. What is the sum of their present ages?
A30 years
B24 years
C33 years
D27 years
Show answer & solution
Answer: D. 27 years
Solution
Let present ages be a and b.
(a - 3)/(b - 3) = 3/4 gives 4a = 3b + 3
(a + 3)/(b + 3) = 5/6 gives 6a = 5b - 3
From the first, a = (3b + 3)/4; put in the second: 6 (3b + 3)/4 = 5b - 3
18b + 18 = 20b - 12, so b = 15 and a = 12
Sum = 27 years
Answer: 27 years