Solve for x: 3x + 7 = 28.
- A7
- B9
- C21
- D5
Show answer & solution
Answer: A. 7
Solution
3x = 28 - 7 = 21 x = 21/3 = 7 Answer: 7
Solving equations, roots and comparing quantities.
45 solved questions · 15 easy · 20 medium · 10 hard
Take a 10-question quiz on Linear & Quadratic Equations, no loginTry each one first, then open the answer and the step-by-step solution.
Solve for x: 3x + 7 = 28.
Answer: A. 7
Solution
3x = 28 - 7 = 21 x = 21/3 = 7 Answer: 7
If 5x - 12 = 3x + 8, find x.
Answer: B. 10
Solution
5x - 3x = 8 + 12 2x = 20 x = 10 Answer: 10
The sum of two numbers is 45 and their difference is 9. Find the larger number.
Answer: C. 27
Solution
Larger = (45 + 9)/2 = 27 Smaller = (45 - 9)/2 = 18 Answer: 27
Shortcut: Larger = (sum + difference)/2.
Three times a number increased by 8 equals 50. What is the number?
Answer: D. 14
Solution
3x + 8 = 50 3x = 42 x = 14 Answer: 14
What is the sum of the roots of x² - 9x + 20 = 0?
Answer: A. 9
Solution
Sum of roots = -b/a = -(-9)/1 = 9 (Roots are 4 and 5, 4 + 5 = 9) Answer: 9
What is the product of the roots of x² - 7x + 12 = 0?
Answer: B. 12
Solution
Product of roots = c/a = 12/1 = 12 (Roots 3 and 4) Answer: 12
Find the roots of x² - 5x + 6 = 0.
Answer: C. 2 and 3
Solution
x² - 5x + 6 = (x - 2)(x - 3) = 0 x = 2 or x = 3 Answer: 2 and 3
Find the larger root of x² + 2x - 15 = 0.
Answer: D. 3
Solution
x² + 2x - 15 = (x + 5)(x - 3) = 0 x = -5 or 3 Larger root = 3 Answer: 3
Find the sum of three consecutive integers if the smallest is 17.
Answer: A. 54
Solution
Numbers: 17, 18, 19 Sum = 54 Answer: 54
A father is 4 times as old as his son. The sum of their ages is 60 years. Find the son's age.
Answer: B. 12
Solution
Let son = x, father = 4x 5x = 60 x = 12 Answer: 12 years
If 4 pens and 3 pencils cost ₹50 and each pen costs ₹8, find the cost of one pencil.
Answer: C. 6
Solution
4 pens = 4 x 8 = ₹32 3 pencils = 50 - 32 = ₹18 One pencil = ₹6 Answer: ₹6
Find the discriminant of 2x² - 5x + 3 = 0.
Answer: D. 1
Solution
D = b² - 4ac = 25 - 4(2)(3) = 25 - 24 = 1 Answer: 1
Solve: x/3 + x/6 = 9.
Answer: A. 18
Solution
LCM 6: (2x + x)/6 = 9 3x/6 = 9 so x/2 = 9 x = 18 Answer: 18
If 2x + 3y = 12 and x = 3, find y.
Answer: B. 2
Solution
2(3) + 3y = 12 3y = 6 y = 2 Answer: 2
Which statement is true for x² + 4x + 5 = 0?
Answer: C. No real roots because D = -4
Solution
D = 16 - 4(1)(5) = 16 - 20 = -4 < 0 So there are no real roots. Answer: No real roots because D = -4
Solve the two equations and compare x and y. I. x² - 7x + 12 = 0 II. y² - 3y + 2 = 0
Answer: A. x is greater than y
Solution
I. x² - 7x + 12 = 0 gives x = 3, 4 II. y² - 3y + 2 = 0 gives y = 1, 2 Every value of x is greater than every value of y. Answer: x is greater than y
Shortcut: List the roots on a number line; compare the smallest and largest of each side.
Solve the two equations and compare x and y. I. x² + 7x + 10 = 0 II. y² - 4y + 3 = 0
Answer: B. x is less than y
Solution
I. x² + 7x + 10 = 0 gives x = -5, -2 II. y² - 4y + 3 = 0 gives y = 1, 3 Every value of x is smaller than every value of y. Answer: x is less than y
Shortcut: List the roots on a number line; compare the smallest and largest of each side.
Solve the two equations and compare x and y. I. x² - 9 = 0 II. y² - y - 2 = 0
Answer: D. Relation cannot be established
Solution
I. x² - 9 = 0 gives x = -3, 3 II. y² - y - 2 = 0 gives y = -1, 2 x is greater than y for some pairs and smaller for others, so no fixed relation can be established. Answer: Relation cannot be established
Shortcut: List the roots on a number line; compare the smallest and largest of each side.
Solve the two equations and compare x and y. I. x² - 8x + 16 = 0 II. y² - 8y + 16 = 0
Answer: C. x equals y
Solution
I. x² - 8x + 16 = 0 gives x = 4 II. y² - 8y + 16 = 0 gives y = 4 x = y in every case. Answer: x equals y
Shortcut: List the roots on a number line; compare the smallest and largest of each side.
Solve the two equations and compare x and y. I. x² - 9x + 14 = 0 II. y² - 4y + 3 = 0
Answer: D. Relation cannot be established
Solution
I. x² - 9x + 14 = 0 gives x = 2, 7 II. y² - 4y + 3 = 0 gives y = 1, 3 x is greater than y for some pairs and smaller for others, so no fixed relation can be established. Answer: Relation cannot be established
Shortcut: List the roots on a number line; compare the smallest and largest of each side.
Solve the two equations and compare x and y. I. x² + 7x + 6 = 0 II. y² + 6y + 8 = 0
Answer: D. Relation cannot be established
Solution
I. x² + 7x + 6 = 0 gives x = -6, -1 II. y² + 6y + 8 = 0 gives y = -4, -2 x is greater than y for some pairs and smaller for others, so no fixed relation can be established. Answer: Relation cannot be established
Shortcut: List the roots on a number line; compare the smallest and largest of each side.
Solve the two equations and compare x and y. I. 3x - 15 = 0 II. y² - 4y + 3 = 0
Answer: A. x is greater than y
Solution
I. 3x - 15 = 0 gives x = 5 II. y² - 4y + 3 = 0 gives y = 1, 3 Every value of x is greater than every value of y. Answer: x is greater than y
Shortcut: List the roots on a number line; compare the smallest and largest of each side.
Solve the two equations and compare x and y. I. x² - 49 = 0 II. y² - 17y + 72 = 0
Answer: B. x is less than y
Solution
I. x² - 49 = 0 gives x = -7, 7 II. y² - 17y + 72 = 0 gives y = 8, 9 Every value of x is smaller than every value of y. Answer: x is less than y
Shortcut: List the roots on a number line; compare the smallest and largest of each side.
If 2x + 3y = 17 and x - y = 1, find x.
Answer: D. 4
Solution
From x - y = 1: y = x - 1 2x + 3(x - 1) = 17 5x = 20 x = 4 (and y = 3) Answer: 4
If 3x + 2y = 26 and 5x - 2y = 6, find x + y.
Answer: A. 11
Solution
Add the equations: 8x = 32 so x = 4 3(4) + 2y = 26 so 2y = 14, y = 7 x + y = 11 Answer: 11
The product of two consecutive positive integers is 156. Find their sum.
Answer: B. 25
Solution
n(n + 1) = 156 so n² + n - 156 = 0 (n + 13)(n - 12) = 0, n = 12 Numbers 12 and 13, sum = 25 Answer: 25
Shortcut: Find the number whose square is just below 156: 12 x 13 = 156.
The product of two consecutive even positive integers is 168. Find their sum.
Answer: C. 26
Solution
n(n + 2) = 168 so n² + 2n - 168 = 0 (n + 14)(n - 12) = 0, n = 12 Numbers 12 and 14, sum = 26 Answer: 26
The length of a rectangle is 3 m more than its breadth and its area is 70 m². Find its perimeter (in m).
Answer: D. 34
Solution
Let breadth = b, then b(b + 3) = 70 b² + 3b - 70 = 0, (b + 10)(b - 7) = 0, b = 7 Length = 10 Perimeter = 2(7 + 10) = 34 m Answer: 34 m
A rectangle has perimeter 36 cm and area 77 cm². Find its longer side (in cm).
Answer: A. 11
Solution
l + b = 18 and lb = 77 l and b are roots of t² - 18t + 77 = 0 (t - 7)(t - 11) = 0 Longer side = 11 cm Answer: 11 cm
For what positive value of k does x² + kx + 25 = 0 have equal roots?
Answer: B. 10
Solution
Equal roots need D = 0 k² - 4(1)(25) = 0 k² = 100, k = 10 (positive) Answer: 10
For what value of k does 2x² - 8x + k = 0 have equal roots?
Answer: C. 8
Solution
D = 64 - 8k = 0 k = 8 Answer: 8
If α and β are the roots of x² - 8x + 10 = 0, find α² + β².
Answer: D. 44
Solution
α + β = 8, αβ = 10 α² + β² = (α + β)² - 2αβ = 64 - 20 = 44 Answer: 44
Shortcut: Square the sum, subtract twice the product.
If α and β are the roots of x² - 5x + 3 = 0, find 1/α + 1/β.
Answer: A. 5/3
Solution
α + β = 5, αβ = 3 1/α + 1/β = (α + β)/αβ = 5/3 Answer: 5/3
The present ages of A and B are in the ratio 3 : 5. After 6 years the ratio becomes 2 : 3. Find B's present age (in years).
Answer: B. 30
Solution
Let ages be 3k and 5k (3k + 6)/(5k + 6) = 2/3 9k + 18 = 10k + 12 so k = 6 B = 5 x 6 = 30 years Answer: 30
If x + y = 10 and xy = 21, find x² + y².
Answer: C. 58
Solution
x² + y² = (x + y)² - 2xy = 100 - 42 = 58 Answer: 58
Solve the two equations and compare x and y. I. 2x² - 7x + 6 = 0 II. 3y² - 11y + 10 = 0
Answer: D. Relation cannot be established
Solution
I. 2x² - 7x + 6 = 0 gives x = 3/2, 2 II. 3y² - 11y + 10 = 0 gives y = 5/3, 2 x is greater than y for some pairs and smaller for others, so no fixed relation can be established. Answer: Relation cannot be established
Shortcut: With fractional roots, convert to decimals first (e.g. 3/2 = 1.5, 5/3 = 1.67).
Solve the two equations and compare x and y. I. 2x² - 9x + 10 = 0 II. 4y² - 8y + 3 = 0
Answer: A. x is greater than y
Solution
I. 2x² - 9x + 10 = 0 gives x = 2, 5/2 II. 4y² - 8y + 3 = 0 gives y = 1/2, 3/2 Every value of x is greater than every value of y. Answer: x is greater than y
Shortcut: With fractional roots, convert to decimals first (e.g. 3/2 = 1.5, 5/3 = 1.67).
If x + 1/x = 5, find x² + 1/x².
Answer: B. 23
Solution
(x + 1/x)² = x² + 2 + 1/x² 25 = x² + 1/x² + 2 x² + 1/x² = 23 Answer: 23
If x + 1/x = 4, find x³ + 1/x³.
Answer: C. 52
Solution
x³ + 1/x³ = (x + 1/x)³ - 3(x + 1/x) = 64 - 12 = 52 Answer: 52
Pipe A alone fills a tank 6 hours faster than pipe B alone. Together they fill it in 4 hours. How long does A alone take (in hours)?
Answer: D. 6
Solution
Let A take t hours, B takes t + 6 1/t + 1/(t + 6) = 1/4 4(2t + 6) = t(t + 6) t² - 2t - 24 = 0, (t - 6)(t + 4) = 0, t = 6 Check: 1/6 + 1/12 = 1/4 Answer: 6 hours
A train covers 120 km at a uniform speed. Had its speed been 10 km/h more, it would have taken 1 hour less. Find its speed (in km/h).
Answer: A. 30
Solution
120/v - 120/(v + 10) = 1 1200 = v(v + 10), v² + 10v - 1200 = 0 (v + 40)(v - 30) = 0, v = 30 Check: 120/30 = 4 h, 120/40 = 3 h Answer: 30 km/h
If α and β are the roots of 2x² - 6x + 3 = 0, find α/β + β/α.
Answer: B. 4
Solution
α + β = 3, αβ = 3/2 α² + β² = 9 - 3 = 6 α/β + β/α = 6/(3/2) = 4 Answer: 4
In x² - 9x + k = 0 one root is twice the other. Find k.
Answer: C. 18
Solution
Let roots be a and 2a: 3a = 9 so a = 3 Roots 3 and 6, k = 3 x 6 = 18 Answer: 18
A quadratic has roots that are each 2 more than the roots of x² - 5x + 6 = 0. Which equation is it?
Answer: D. x² - 9x + 20 = 0
Solution
Original roots 2, 3; new roots 4, 5 Sum = 9, product = 20 Equation: x² - 9x + 20 = 0 Answer: x² - 9x + 20 = 0
A positive number exceeds its reciprocal by 8/3. Find the number.
Answer: A. 3
Solution
x - 1/x = 8/3 3x² - 3 = 8x, 3x² - 8x - 3 = 0 (3x + 1)(x - 3) = 0, x = 3 or -1/3 Positive number = 3 Check: 3 - 1/3 = 8/3 Answer: 3
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